Elections in Rhode Island |
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The 1808 United States presidential election in Rhode Island took place as part of the 1808 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.
Rhode Island voted for the Federalist candidate, Charles C. Pinckney, over the Democratic-Republican candidate, James Madison. Pinckney won Rhode Island by a margin of 53.30%.
Results
1808 United States presidential election in New Hampshire[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Federalist | Charles C. Pinckney | 3,072 | 53.30% | 4 | |
Democratic-Republican | James Madison | 2,692 | 46.70% | – | |
Totals | 5,764 | 100.00% | 4 |
See also
References
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 31, 2024.