Molybdenum(V) fluoride is an inorganic compound with the formula MoF5. It is a hygroscopic yellow solid. Like most pentafluorides, it exists as a tetramer.[2]
Production
Molybdenum(V) fluoride is produced by the reaction of molybdenum and molybdenum hexafluoride:[3]
- Mo + 5 MoF6 → 6 MoF5
It can also be prepared by the reduction of molybdenum hexafluoride with phosphorus trifluoride or tungsten hexacarbonyl, or by the oxidation of elemental molybdenum with fluorine at 900 °C.[3]
About 165 °C, it disproportionates to the tetra- and hexafluoride:[1]
- 2 MoF5 → MoF4 + MoF6
References
- ^ a b c Stene, Riane E.; Scheibe, Benjamin; Pietzonka, Clemens; Karttunen, Antti J.; Petry, Winfried; Kraus, Florian (2018). "MoF5 revisited. A comprehensive study of MoF5". Journal of Fluorine Chemistry. 211: 171–179. doi:10.1016/j.jfluchem.2018.05.002. ISSN 0022-1139. S2CID 103463040.
- ^ Edwards, A. J. (1969). "Crystal Structure of tungsten pentafluoride". J. Chem. Soc. A: 909. doi:10.1039/J19690000909.
- ^ a b T. J. Ouellette, C. T. Ratcliffe, D. W. A. Sharp, A. M. Steven (1972). "Molybdenum(V) Fluoride (Molybdenum Pentafluoride)". Molybdenum(V) Fluoride (Molybdenum pentalfluoride). Inorganic Syntheses. Vol. 13. pp. 146–150. doi:10.1002/9780470132449.ch28. ISBN 9780470132449.
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