Lutetium(III) hydroxide is an inorganic compound with the chemical formula Lu(OH)3.

Production

Reacting lutetium chloride and alkalis will first produce Lu(OH)2Cl, then it will become Lu(OH)2.5Cl0.5. Finally, the reaction will produce Lu(OH)3.[2]

LuCl3+2 NaOH→Lu(OH)2Cl+2 NaCl
Lu(OH)2Cl+0.5 NaOH→Lu(OH)2.5Cl0.5+0.5 NaCl
Lu(OH)2.5Cl0.5+0.5 NaOH→Lu(OH)3+0.5 NaCl

Chemical properties

Lutetium(III) hydroxide can react with acid and form lutetium(III) salts：

Lu(OH)3 + 3 H+ → Lu3+ + 3 H2O

While heating lutetium(III) hydroxide, it will produce LuO(OH), continued heating could produce Lu2O3.[1]

References

  1. ^ a b Yi, Xianwu; et al. Series of Inorganic Chemistry. Vol 7. Scandium, Rare Earth Elements. Science Press. pp 168-171. (2) Hydroxides.
  2. ^ Aksel'rud, N. V.; Akhrameeva, T. I. Basic chlorides and hydroxide of lutetium. Zhurnal Neorganicheskoi Khimii, 1962. 7. pp 1998-2001. ISSN 0044-457X.
Allikas: http://en.wikipedia.org/wiki/Lutetium(III)_hydroxide
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