Hardin Township is located in Pike County, Illinois. As of the 2010 census, its population was 212 and it contained 105 housing units.[2]

Geography

According to the 2010 census, the township encompasses an area of 37.41 square miles (96.9 km2), of which 37.39 square miles (96.8 km2) (or 99.95%) is land and 0.03 square miles (0.078 km2) (or 0.08%) is water.[2]

Demographics

Historical population
CensusPop.Note%±
2016 (est.)206[1]
U.S. Decennial Census[3]

References

  1. ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
  3. ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.

39°31′42″N 90°44′49″W / 39.52833°N 90.74694°W / 39.52833; -90.74694


Allikas: Https://en.wikipedia.org/wiki/Hardin_Township,_Pike_County,_Illinois
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