Samarium(III) iodide is an inorganic compound, a salt of samarium and hydroiodic acid with the chemical formula SmI
3.[1][2]

Synthesis

Samarium(III) iodide is prepared by the reaction of metallic samarium and iodine:[3]

2 Sm + 3 I2 → 2 SmI3

Properties

Samarium(III) iodide is a yellow powder that is unstable in air and decomposes in water (hydrolysis).[1] When heated with metallic samarium, it forms samarium diiodide:[4]

2SmI3 + Sm → 3 SmI2

Reduction by hydrogen also affords samarium diiodide upon heating:

2 SmI3 + H2 → 2 SmI2 + 2 HI

Applications

The compound is commercially available and used in organic reactions as a catalyst.[1]

References

  1. ^ a b c Zhang, Yuanmin (6 November 2011). "Samarium Triiodide". Synlett. 2011 (11): 1638–1639. doi:10.1055/s-0030-1260781.
  2. ^ "Samarium(III) Iodide". American Elements. American Elements. Retrieved 8 August 2021.
  3. ^ Molodkin, A. K.; Karagodina, A. M.; Tupolev, V. S.; Dudareva, A. G.; Prokhina, A. G. (1984). "Iodination of samarium and reaction of samarium triiodide with lithium iodide". Zhurnal Neorganicheskoj Khimii (in Russian). 29 (4): 1069–1072. ISSN 0044-457X. Retrieved 8 August 2021.
  4. ^ Imamoto, Tsuneo; Ono, Mitsumasa (5 March 1987). "The Reaction of Samarium(III) Iodide with Samarium Metal in Tetrahydrofuran, A New Method for the Preparation of Samarium(II) Iodide". Chemistry Letters. 16 (3): 501–502. doi:10.1246/cl.1987.501. ISSN 0366-7022.
Allikas: https://en.wikipedia.org/wiki/Samarium(III)_iodide
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