The 1816 United States presidential election in Rhode Island took place as part of the 1816 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.

Rhode Island voted for the Democratic-Republican candidate, James Monroe. Monroe won Rhode Island by a margin of 100.00%. Because the Federalist challenger in the nation, Rufus King, was not on the ballot.

Results

1816 United States presidential election in Rhode Island[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Monroe 1,236 100.00% 4
Federalist Rufus King (not on ballot) 0
Totals 1,236 100.0% 4

See also

References

  1. ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 31, 2024.
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