| Elections in Wyoming |
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There were two United States House of Representatives elections in Wyoming in 1890, both held on September 11, 1890. The first was for the 51st United States Congress, with a term expiring on March 4, 1891; this election was necessary due to Wyoming's admittance to the Union as the 44th state earlier in 1890. The second election was for the full term in the 52nd United States Congress beginning on March 4, 1891. Republican lawyer Clarence D. Clark defeated Democratic George T. Beck with about 58% of the vote in both elections and became the first person to represent Wyoming in the House of Representatives.
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Clarence D. Clark | 9,087 | 58.22% | |
| Democratic | George T. Beck | 6,520 | 41.78% | |
| Total votes | 15,607 | 100% | ||
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Clarence D. Clark | 8,751 | 58.46% | |
| Democratic | George T. Beck | 6,219 | 41.54% | |
| Total votes | 14,970 | 100% | ||
References
- ^ a b Wyoming Secretary of State (1897). "Appendix B". Report of the Secretary of State of State of Wyoming for the Period Ending Sept. 30 1896. Cheyenne, Wyoming: The S. A. Bristol Company, Printers and Bookbinders. pp. xxiv.