Shepherd Hill (New York)
| Shepherd Hill | |
|---|---|
  Shepherd Hill Location of Shepherd Hill within New York  Shepherd Hill Shepherd Hill (the United States) | |
| Highest point | |
| Elevation | 492 feet (150 m) |
| Coordinates | 43°11′01″N 75°35′45″W / 43.18361°N 75.59583°W[1] |
| Geography | |
| Location | NW of Verona, New York, U.S. |
| Topo map | USGS Verona |
Shepherd Hill is a summit located in Central New York Region of New York located in the Town of Verona in Oneida County, northwest of Verona.
References
- ^ "Shepherd Hill". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved December 8, 2017.