The 1988 Men's Hockey Champions Trophy was the tenth edition of the Hockey Champions Trophy men's field hockey tournament. It took place from Mar 25-Apr 1 in Lahore, Pakistan.[1]
Tournament
Final table
| Team | Pld | W | D | L | GF | GA | GD | Pts |
|---|---|---|---|---|---|---|---|---|
 West Germany
|
5 | 4 | 0 | 1 | 11 | 5 | +6 | 8 |
 Pakistan
|
5 | 3 | 2 | 0 | 9 | 3 | +6 | 8 |
 Australia
|
5 | 2 | 2 | 1 | 6 | 4 | +2 | 6 |
 Soviet Union
|
5 | 1 | 3 | 1 | 6 | 6 | 0 | 5 |
 Spain
|
5 | 1 | 1 | 3 | 4 | 10 | −6 | 3 |
 Great Britain
|
5 | 0 | 0 | 5 | 3 | 11 | −8 | 0 |
Source: fih.ch
Results
| Team One | Team Two | Score |
|---|---|---|
| Spain |
Great Britain |
2-1 |
| Australia |
West Germany |
0-1 |
| Pakistan |
Soviet Union |
1-1 |
| Great Britain |
Australia |
0-2 |
| West Germany |
Soviet Union |
3-1 |
| Pakistan |
Spain |
4-0 |
| Great Britain |
Soviet Union |
1-3 |
| Spain |
Australia |
1-2 |
| West Germany |
Pakistan |
1-2 |
| Soviet Union |
Australia |
1-1 |
| West Germany |
Spain |
3-1 |
| Great Britain |
Pakistan |
0-1 |
| Soviet Union |
Spain |
0-0 |
| Great Britain |
West Germany |
1-3 |
| Australia |
Pakistan |
1-1 |
References
- ^ "Champions Trophy 1988". FIH.