1817 Georgia gubernatorial election

1817 Georgia gubernatorial election
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November 10, 1817
1819 →
 
Nominee William Rabun John Clark
Party Democratic-Republican Democratic-Republican
Popular vote 62 57
Percentage 52.10% 47.90%
Governor before election

William Rabun (Acting)
Democratic-Republican

Elected Governor

William Rabun
Democratic-Republican

The 1817 Georgia gubernatorial election was held on November 10, 1817, in order to elect the Governor of Georgia. Democratic-Republican candidate and incumbent acting Governor William Rabun defeated fellow Democratic-Republican candidate John Clark in a Georgia General Assembly vote.[1]

General election

On election day, November 10, 1817, Democratic-Republican candidate William Rabun won the election against his opponent fellow Democratic-Republican candidate John Clark. Rabun was officially sworn in as the 29th Governor of Georgia on November 10, 1817.[2]

Results

Georgia gubernatorial election, 1817[3]
Party Candidate Votes %
Democratic-Republican William Rabun 62 52.10
Democratic-Republican John Clark 57 47.90
Total votes 119 100.00
Democratic-Republican hold

References

  1. ^ "Georgia 1817 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University. Retrieved 2023-12-08.
  2. ^ "GA Governor". ourcampaigns.com. July 18, 2022. Retrieved 2023-12-08.
  3. ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
allikas: http://en.wikipedia.org/wiki/1817_Georgia_gubernatorial_election