| Elections in Ohio |
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The 1812 United States presidential election in Ohio took place as part of the 1812 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio re-elected incumbent Democratic-Republican President James Madison over Federalist candidate DeWitt Clinton. Madison won Ohio by a margin of 38.42%.
Results
| 1816 United States presidential election in Ohio[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Madison (incumbent) | 7,420 | 69.21% | 8 | |
| Federalist | DeWitt Clinton | 3,301 | 30.79% | 0 | |
| Totals | 10,721 | 100.0% | 8 | ||
See also
Notes
- ^ While commonly labeled as the Federalist candidate, Clinton technically ran as a Democratic-Republican and was not nominated by the Federalist party itself, the latter simply deciding not to field a candidate. This did not prevent endorsements from state Federalist parties (such as in Pennsylvania), but he received the endorsement from the New York state Democratic-Republicans as well
References
- ^ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved December 8, 2019.
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