| Elections in New Jersey |
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The 1864 United States presidential election in New Jersey took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
New Jersey voted for the Democratic candidate, George B. McClellan, over the National Union candidate, incumbent president Abraham Lincoln. McClellan won his home state by a narrow margin of 5.68%. New Jersey was one of the three states McClellan won, with the other two being Delaware and Kentucky.
With 52.84% of the popular vote, New Jersey would prove to be McClellan's second strongest after Kentucky.[1]
Results
| 1864 United States presidential election in New Jersey[2] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | George B. McClellan | 68,024 | 52.84% | 7 | |
| National Union | Abraham Lincoln (incumbent) | 60,723 | 47.16% | 0 | |
| Totals | 128,747 | 100.0% | 7 | ||
See also
References
- ^ "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ^ "1864 Presidential General Election Results - New Jersey".
State results of the 1864 U.S. presidential election | ||
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