The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Rhode Island by a margin of 13.86%.

Jackson remains the only Democrat to win two consecutive terms without carrying Rhode Island either time.

Results

1832 United States presidential election in Rhode Island[1]
Party Candidate Votes Percentage Electoral votes
National Republican Henry Clay 2,810 56.93% 4
Democratic Andrew Jackson (incumbent) 2,126 43.07% 0
Totals 4,936 100.0% 4

See also

References

  1. ^ "1832 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved April 12, 2013.
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